a block of ice slides down a frictionless ramp at angle = 50°, while an ice worker pulls up the ramp?

Question

(via a rope) with a force of magnitude Fr = 45 N. As the block slides through distance d = 0.25 m along the ramp, its kinetic energy increases by 90 J. How much greater would its kinetic energy have been if the rope had not been attached to the block?

Answer 1

The energy contributions to KE are
PE=m*g*sin(50)*.25
Work done by the force
-45*.25
this sums to 90 J
without the rope attached, the KE would increase by
45/4

j

Answer 2

Since work done on the block will be equal to the increase in the kinetic energy of the box we can equate the net force on the block multiplied with the distance it travels to 80J i.e the equation will look like "{[mass X acceleration due to gravity(9.8) X Sin θ] - 50} X .5 = 80" .Input all the known values those are everything other than mass of the object. Find the mass. Since the work done if there were no rope would be mass X acceleration due to gravity X Sin θ X .5 calculate this value which will turn out to be 210(appx). but since the question is how much greater would the kinetic energy be therefore we subtract 80 from 210 to get the final answer as 130J.