a sagging door 4 meters by 5 meters is to be made rigid by the addition of a diagonal piece of iron bar.how long must the bar be?
pls. answer dis w/solution. tnx.
2007-10-10 03:18:21 · 9 answers · asked by mhAe c 1 in Science & Mathematics ➔ Mathematics
02
The length of the iron bar must be equal to the diagonal of the rectangular shaped door
It should be sqrt(5^2+4^2)
=sqrt41 m
=6.403 m
2007-10-10 03:25:16 · answer #1 · answered by alpha 7 · 1⤊ 0⤋
If the door is a rectangle, then the situation you are describing is a right triangle. In a right triangle you have two legs perpendicular to each other (i.e., at a 90-degree angle) and a third leg, called the hypotenuse, joining them together.
Pythagoras' Theorem states that the length of the hypotenuse is the square root of the sum of the squares of the legs. That is, C = SQRT(A^2 + B^2). So, if A = 5m and B = 4m, then
C = SQRT(5^2 + 4^2) = SQRT(25 + 16) = SQRT(41) ≈ 6.40m. The diagonal bar should be 6m, 40cm long. I'd include a picture if I could, but I can't.
2007-10-10 03:30:39 · answer #2 · answered by antiochus4epiphanes 1 · 0⤊ 0⤋
It is the hypotenuse of a right triangle.
H^2 = A^2 + B^2
= 4^2 + 5^2
= 16 + 25
= 41
H = sqrt(41) = 6.403 meters
2007-10-10 03:23:47 · answer #3 · answered by Mike1942f 7 · 0⤊ 0⤋
The bar (length c) together with the top (length a) and one side of the door (length b) make a right triangle. Use Pythagorean identity c^2 = a^2 + b^2 = 4^2 + 5^2 = 41, so c = sqrt(41).
It doesn't say where to put the bar so you have to make an assumption. ("diagonal" is not precise)... I'm assuming that the bar goes from a corner of the door to the opposite corner.
2007-10-10 03:22:44 · answer #4 · answered by TurtleFromQuebec 5 · 0⤊ 0⤋
to find the hypotenuse of any right triangle use the formula a^2 + b^2 = c^2 where c is the hypotenuse and a and b are the sides adjacent to the right triangle so...
a=4
b=5
a^2 + b^2 = 16 + 25
c^2 = 41
the square root of 41 is 6.4 meters
2007-10-10 03:23:30 · answer #5 · answered by nutsnflats 2 · 0⤊ 0⤋
if door is 4m by 5m and you need to no the diagonal distance use the formula
a^2 = b^2 + c^2
where a is diagonal lenght
b is height
c is width
a^2 = 4^2 + 5^2
a^2 = 16 + 25
a^2 = 41
a = 6.403124237m
2007-10-10 03:25:24 · answer #6 · answered by Anonymous · 0⤊ 0⤋
4 squared + 5 squared= c c is third side
16+25=41 squared
square root of 41 is 6.40
2007-10-10 03:23:25 · answer #7 · answered by Anonymous · 0⤊ 0⤋
4 squared plus 5 squared equals what...
16 + 25 = 41
the square root of 41 equals....
what?
whatever it equals is the answer (in meters)
2007-10-10 03:21:37 · answer #8 · answered by Anonymous · 0⤊ 0⤋
A2 + B2 = C so something like 5x5 + 4x4 and that = the diagonal peice
2007-10-10 03:21:47 · answer #9 · answered by amber w 1 · 0⤊ 0⤋