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Solve 5x + 4y = 12 for y

2007-10-10 02:37:58 · 11 answers · asked by jllanos73 2 in Science & Mathematics Mathematics

11 answers

5x + 4y = 12
4y = 12 - 5x

y = 12/4 - 5/4x

y = 3 - 5/4x

2007-10-10 02:54:31 · answer #1 · answered by Dr W 7 · 1 0

if you mean solve for nonegative integers x and y ... here it is :

5x + 4y = 12

4 divides 5x implies 4 divides x so, let x =4k for some nonnegative integer k.

5k + y = 3

If k>=1 a contradiction is obvious for the left hand side will be larger than 3 = right hand side. So k = 0.

Thus y = 3. and x =0.

Done.

If you allowed negative integers, then there are infinitely many solutions ... we proceed as follows... from
5k + y = 3 we get y = 3 - 5k. and x = 4k.
For any integer value of k be it positive, zero or negative, we will always get the solution in integers for x and y though one of x and y will have to be a negative integer.

In other words, the solution is:

NO solutions in positive integers x and y.

One solution for x=0, where y=3.

(x,y) = ( 4k, 3 - 5k) for all integers k. And in this case at least one of x or y will have to be negative or zero. Note that this also includes the solution (x,y) = (0,3) above... Just put k=0.

If you were just looking to mean y as ANY real number, then the solution is just,

y = ( 12 - 5x ) / 4 for any real x.

Hope this helped.

:)

2007-10-10 10:24:29 · answer #2 · answered by jonny boy 3 · 0 0

5x + 4y = 12 : subtract 5x from both sides

4y = 12 - 5x : Divide each term by 4

y = 3 - 5/4 x

2007-10-10 09:42:16 · answer #3 · answered by remowlms 7 · 1 0

you only have one equation there with 2 unknowns, so there will be infinitely many sets of solutions.

you can however show how the value of y depends on x, simply be rearranging the equation:

5x + 4y = 12
4y = 12 - 5x
y = 3 - (5/4)x

so whatever the x value is, y will be (3 - (5/4)x)

2007-10-10 09:41:45 · answer #4 · answered by Ian C 2 · 0 0

5x + 4y = 12

Do the same operation on both sides until you get the desired result

4y = - 5x + 12 {subtract 5x}

y = - 5x/4 + 3 {divide by 4}

2007-10-10 09:43:58 · answer #5 · answered by kindricko 7 · 1 0

5x + 4y = 12
4y = 12 -5x
y= (12-5x)/4

2007-10-10 09:51:26 · answer #6 · answered by slylar 2 · 0 0

4y = 12 - 5x
y = 3 - ( 5 / 4 ) x
or
y = - ( 5 / 4 ) x + 3

2007-10-11 03:13:37 · answer #7 · answered by Como 7 · 0 0

4y = 12 - 5x
y = 3 + (5/4)x

2007-10-10 09:40:57 · answer #8 · answered by TurtleFromQuebec 5 · 0 2

What I would do is substitute a zero in for x to clear the x's adn then solve for y

5(0) + 4y = 12
4y = 12
y = 3

2007-10-10 09:41:35 · answer #9 · answered by Ms. Exxclusive 5 · 0 4

you can't, atleast not as a number,
It is (12-5X)/4

2007-10-10 09:40:55 · answer #10 · answered by Greg G 5 · 0 1

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