English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

free surface of a large water reservoir that can supply water at a rate of 1500 kg/s steadily. Determine the power generation potential

2007-10-08 06:53:51 · 1 answers · asked by Kai K 1 in Science & Mathematics Engineering

1 answers

HP = GPM*H/3,960

1,500Kg/sec = 330.033Gal/sec = 19,802GPM

H = 120 M = 393.7 ft

HP = 19,802*393.7/3,960 = 1,968.7 HP*0.80 = 1,575 BHP

1,575 BHP = 1,174.5 KW

2007-10-08 14:20:07 · answer #1 · answered by gatorbait 7 · 0 0

fedest.com, questions and answers