A hydroelectric power plant, 100m^3/s of water flows from an elevation of 120m to a turbine, where electric..?

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A hydroelectric power plant, 100m^3/s of water flows from an elevation of 120m to a turbine, where electric..?

power is generated. The overall efficiency of the turbine-generator is 80 percent. Disregarding frictional losses in piping, estimate the electric power output of this plant.

2007-10-07 07:40:57 · 1 answers · asked by s4_orce 1 in Science & Mathematics ➔ Engineering

1 answers

Hydraulic Horsepower = GPM*h/3960

100 cubic meters per second = 1,585,032 GPM

120 meters = 393.7 feet

Hydraulic Horsepower = 1,585,032*393.7/3960 = 157,582.6 HP

At 80% efficiency, the Brake Hydraulic Horsepower = 0.8*157,582.6 = 126,066 BHP

1HP = 0.757 KW

126,066 BHP*0.757 = 95,432 KW

2007-10-07 11:59:01 · answer #1 · answered by gatorbait 7 · 0⤊ 0⤋