2007-10-07 06:03:42 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
For a DC voltage source (non-periodic), the average value is the RMS value.
For a periodic DC waveform, say a clock signal, with a 50% duty cycle, an amplitude of 5V and a period of 2 seconds:
The average voltage for a cycle would be 2.5V.
The RMS voltage would be [((5V^2 * 1S) + (0V^2 * 1S))/2S]^1/2 or about 3.5V.
For a Square wave with an amplitude of +5V to -5V, with a 50% duty cycle and a period of 2 seconds:
The average value over the cycle is 0V:
The RMS voltage is [((5V^2 * 2S) + (-5V^2 *21S))/2S]^1/2 or 5V.
2007-10-07 07:01:45 · answer #1 · answered by mushroom 2 · 0⤊ 0⤋
It should also be 68 V. RMS (Root Mean Square) is normally only used with AC to describe the 'equivalent energy' DC value.
Doug
2007-10-07 06:14:48 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
?? Is there something else to this question? DC does not have an RMS value.
2016-05-18 01:00:07 · answer #3 · answered by ? 3 · 0⤊ 0⤋