A building casts a shadow 21 m. long when the elevation of the sun is 35°.How high is the top of the building?

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A building casts a shadow 21 m. long when the elevation of the sun is 35°.How high is the top of the building?

2007-10-05 19:17:11 · 4 answers · asked by nowaytoyou 1 in Science & Mathematics ➔ Mathematics

4 answers

use trigonometry:
shadow is the adjacent side, so use tan
i.e.
tan35 = O/21
21tan35 = O ( O is the opposite side, and the height of the building)
it gives a height of: 14.7m

2007-10-05 19:22:44 · answer #1 · answered by kiwi25 3 · 0⤊ 0⤋

H = 21 tan 35 = 14.704 m

2007-10-06 02:23:14 · answer #2 · answered by CPUcate 6 · 0⤊ 0⤋

tan 35Â° = h / 21
h = 21 tan 35Â°
h = 14.7 m

2007-10-06 03:09:40 · answer #3 · answered by Como 7 · 1⤊ 0⤋

h=21*tan35'=21*0.7=14.70m

2007-10-06 02:23:45 · answer #4 · answered by Anonymous · 0⤊ 0⤋