Here is my best guess. Just so you don't think you're doing my homework. I am looking for confirmation of my answer.
vertex is at (3, 1)
http://www.mackendrick.com/images/vertex.jpg
2007-10-05 16:37:51 · 3 answers · asked by Talriada 2 in Science & Mathematics ➔ Mathematics
yes... rearrange the quadratic...
(s-1) = (r-3)^2 ... the dependent variable is s.
it has the vertex at (3,1)... and it is concave upward...
it is similar to the graph of y=x^2 ... but with the vertex translated.
you are correct.
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2007-10-05 21:32:35 · answer #1 · answered by Alam Ko Iyan 7 · 0⤊ 1⤋
I'm assuming you want s as the independent?
s = (r-3)^2 + 1
so it's the graph of r^2 translated 1 unit up and 3 units right
2007-10-05 16:42:05 · answer #2 · answered by sirfastolfe 2 · 1⤊ 0⤋
r is horizontal axis
s is vertical axis
s ( r ) = (r - 3) ² + 1
s ( r ) = r ² - 6 r + 10
s `( r ) = 2 r - 6 = 0 for turning point
r = 3 for turning point
(3,1) is a turning point. (vertex)
Cuts vertical axis at (-3)² + 1 = 10
Does not cut horizontal axis.
2007-10-06 05:51:30 · answer #3 · answered by Como 7 · 1⤊ 0⤋