A broken leg is supported in the traction apparatus shown. If the hanging mass has a value of M = 23.5 kg, (a) what is the tension T1 in the rope, and (b) what is the total force F applied to the leg?
(a) T1 = 231 ± 3.0% N
(b) F = 399 ± 3.0% N
how do they get the answer for A
there is also a picture and here it is
http://img76.imageshack.us/my.php?image=traction0br9.jpg
2007-10-05 14:18:02 · 1 answers · asked by XLR8 2 in Science & Mathematics ➔ Physics
The tension everywhere in the rope is simply the force of the weight, M*g. It doesn't matter how many pulleys or changes in rope direction there are, it all comes down to the fact that the rope tension supports the weight, and once set is the same at all points on the rope.
If you use the mean value for g = 9.822 m/sec^2, you get T1 = 230.817 N. The ±3% must come from the uncertainty in g, but I have not found a reference for that.
2007-10-05 14:29:03 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋