9x2 - 9x - 54 . Factor completely?

Question

9^x - 9x - 54

Answer 1

Since all are divisible by 9:

9 ( x^2 - x - 6); factors of 6 are 1 & 6, 2 & 3 ; use 2 & 3 to get 1, then:

9 [ (x-3) (x+2) ]

You can equate this to 0 so that you can get the values of x, then:

x - 3 = 0, so x = 3
x + 2 = 0, so x = -2

Hence your x is either 3 or -2

Math is good :)

Answer 2

9 (x² - x - 6)
9 (x - 3)(x + 2)

Answer 3

9x^2-9x-54 = 9(x^2-x-6) = 9(x-3)(x+2)