find a number that has a reminder of 6 when divided by 7 and a reminder of 2 when dived by 5 please show your work
2007-10-05 11:47:07 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(x/7) = y + (6/7)
(x/5) = z + (2/5)
x can't be divisible by 7 or 5, because a remainder occurs when it is divided by 7 and 5.
The number must be one less than anumber that is divisible by 7 and 2 bigger than a number that is divisible by 5.
Trial and error. Test all xs that are 1 less than a multiple of 7 to see if they are 2 bigger than a multiple of 5.
x = 6
(6/7) = 0 + (6/7)
(6/5) = 0 + (6/5)
Not a solution.
Let x = 13
(13/7) = 1 + (6/7)
(13/5) = 2 + (3/5)
Not a solution
Let x = 20
Not a solution, because x can't be divisible by 5.
Let x = 27
(27/7) = 3 + (6/7)
(27/5) = 5 + (2/5)
Therefore, 27 is a solution.
2007-10-05 11:57:37 · answer #1 · answered by I can't think of a good name 2 · 0⤊ 0⤋
The number must be 5x+2 to get R =2 when divided by 5
The number must be 7x+6 to get R=6 when divided by 7The number is 62 which results when x = 12
62/5 = 12 R 2
62/7 = 8 R 6
x = 7+5 = 12
2007-10-05 12:08:27 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
27/7 =3R6 27/5 = 5R2
2007-10-05 11:56:45 · answer #3 · answered by Delta/Bravo 3 · 0⤊ 0⤋
some number that im too lazy to figure out
figure it out yourself
2007-10-05 11:53:53 · answer #4 · answered by katie c 2 · 0⤊ 0⤋
27 i didn't do "work" just trial and error
6
2007-10-05 11:53:25 · answer #5 · answered by Anonymous · 0⤊ 0⤋
i really dont know or care, its your homework, you need to do it yourself....
2007-10-05 11:55:22 · answer #6 · answered by Michael H 1 · 0⤊ 0⤋
its your homework do it youself
2007-10-05 11:49:16 · answer #7 · answered by Anonymous · 0⤊ 1⤋