2007-10-05 11:44:33 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
20-3m = -6m + 50
add three m to both sides
20 = -3m + 50
subtract 50 from both sides
-30 = -3m
divide by -3
m = 10
2007-10-05 11:48:24 · answer #1 · answered by superman 4 · 0⤊ 0⤋
Combine like terms:
20 - 3m = 2m -8m +50
20 - 3m = -6m +50
Now add 6m to both sides:
20 -3m +6m = -6m +6m +50
3m +20 = 50
Now subtract 20 from both sides:
3m +20 -20 = 50 -20
3m = 30
Now divide both sides by 3:
3/3m = 30/3
m = 10
Now check your answer...20 - 3(10) = 2(10) -8(10) +50
20 - 30 = 20-80+50
-10 = -60+50
-10 = -10
The solution checks out...
m=10
2007-10-05 11:50:17 · answer #2 · answered by sayamiam 6 · 0⤊ 0⤋
20-3m=2m-8m+50
20 - 50 = 2m +3m - 8m
- 30 = -3m
10 = m
2007-10-05 11:48:45 · answer #3 · answered by ironduke8159 7 · 1⤊ 0⤋
20-3m=2m-8m+50
20 = 3m + 2m - 8m +50
20 = 5m -8m +50
20 - 50 = -3m
-30 = -3m
m = 10
2007-10-05 11:48:44 · answer #4 · answered by I can't think of a good name 2 · 0⤊ 0⤋
20-3m=2m-8m+50 --combine like terms
20-3m=-6m+50
20-3m=50
-3m=30
m= -10
2007-10-05 11:48:57 · answer #5 · answered by Wut?I missed it 3 · 0⤊ 2⤋
20 - 3m = - 6m + 50
3m = 30
m = 10
2007-10-06 02:35:15 · answer #6 · answered by Como 7 · 1⤊ 0⤋