2x^3 + 2x^2y - 40xy2. Factor completely?

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2x^3 + 2x^2y - 40xy2. Factor completely?

2007-10-05 11:32:34 · 3 answers · asked by . 1 in Science & Mathematics ➔ Mathematics

3 answers

2x^3 + 2x^2y - 40xy2
= 2x(x^2 +xy -20y^2)
= 2x(x+5y)(x-4y)

2007-10-05 11:37:21 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋

2x^3+2x^2y-40xy^2 is divisible by 2x. This will give you 2x(x^2+xy-20y^2). x^2+xy-20y^2 will factor to (x+5y)(x-4y). Put 2x in front of this. 2x(x+5y)(x-4y) and there's your answer. Hope you understand how this was done. Good luck with the rest of your homework. Thanks for the 2 points!

2007-10-05 20:59:32 · answer #2 · answered by Emissary 6 · 0⤊ 0⤋

common factor for the three terms are 2x

2x(x^2 + xy - 20y^2)

= 2x(X +5Y)(X - 4Y)

2007-10-05 18:39:30 · answer #3 · answered by norman 7 · 0⤊ 0⤋