Can ne 1 Plz help me out w/ this Physics -102 problem, apreciate it tyty.?

Question

Diagram Description:- there are 4 balls(mass A, B, C, D) and mass of each ball is 2.0kg and their arrangement is in a figure of a square set apart 10cm from each other< sorry couldn't draw figure

QUESTION >>>Find the magnitude of the net gravitational force on mass A

Answer 1

Ok .. hope you understandme without drawings :
You have the force over A coming from B C & D (it means 3 forces) so your total torce will be

Fa=Fb+Fc+Fd

Gravitational Force is Gm1m2/r^2

Then for b and d you have the ball at the same distance right? right and down, the only one different is c

so
Fa=2*(Fb)+Fc

Fb
Gmassa*massb/r^2
G (2)(2)/(0.1)^2

= 400 G

Fc
G massa*massc/r^2
We need to calculate the raduius with a triangle
base and height = .1
if tanget side is c2=a^2+b^2

Then c= sqr root of 2*(.1)^2=.1414 meters or 14.14 cm
Returning to the formula
G (2)(2)/(.1414^2)= 200 G


Then the reponse if
Fa= (400*2+200)G
Fa= 1000G
if G equals 6.67 x 10^-11

Fa= 6.67x10^-11 * 1000 = 6.6x10^-8

hope it helps

Answer 2

If they are all 10cm from each other, they can't be in a square. The one at the opposite corner would be 1.414 as far away. Perhaps a pyramid with all faces and the base an equilateral triangal?