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how do you do the limit as x approaches infinity of arctan (x^5-x^-7)? Thanks

2007-10-05 09:36:22 · 2 answers · asked by ILuvTaraReid 2 in Science & Mathematics Mathematics

2 answers

x^5 - x^(-7) approaches infinity as x approaches infinity. You're basically looking for the arctan(infinity). In other words, the tangent of what is infinity. pi/2.

Keep in mind that the answer can be (2n+1)*pi/2. But it's often accepted that arctan(x) has a range of -pi/2 to pi/2.

2007-10-05 09:46:37 · answer #1 · answered by np_rt 4 · 0 0

1/(tan^-1(x)^2)

2007-10-05 16:43:07 · answer #2 · answered by programhelp 2 · 0 0

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