Find the quotient:
(14y+8y^2+y^3+12) / (6+y)
Thanks for the help!
2007-10-05 08:51:25 · 6 answers · asked by John 1 in Science & Mathematics ➔ Mathematics
Do your own homework.
2007-10-05 08:54:33 · answer #1 · answered by buffytou 6 · 0⤊ 1⤋
14y+8y^5+12/6+y= 14y+8y^5+2
2007-10-05 15:59:22 · answer #2 · answered by i_heart_kasey_kahne9 3 · 0⤊ 0⤋
rearrange it and try y+6 into y^3 + 8y^2 + 14y + 12
you will get y^2+2y+2 with a remainder of zero.
2007-10-05 15:58:34 · answer #3 · answered by J D 5 · 0⤊ 0⤋
first arrange the expression in order
(y^3 + 8y^2 + 14y + 12)/(y +6)
now divide
y + 6)y^3 + 8y^2 +14y+12(y^2
--------y^3 +6y^2
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---------------2y^2 + 14y (2y
----------------2y^2 +12y
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------------------------- 2y +12 (2
-------------------------2y+12
So the quotient is y^2 + 2y + 2
2007-10-05 16:05:20 · answer #4 · answered by mohanrao d 7 · 0⤊ 0⤋
using synthetic division and assuming x + 6 divides exactly with no renainder:-
- 6 |1___8___14___12
""""|___- 6__-12___-12
""""|1___2___2____0
Quotient is y ² + 2 y + 2
2007-10-09 15:16:11 · answer #5 · answered by Como 7 · 0⤊ 0⤋
cant you do it? use a graphing caculator
2007-10-05 15:54:55 · answer #6 · answered by OutdoorsMan 1 · 0⤊ 0⤋