Physics Question.....?

Question

Ok folks out of 20 problems this is the last problem on my review sheet,(I have the answers) but I have the no clue on how to work it out and I'm stuck so please I have an exam this monday and our professor mentioned that there was going to be a similiar question like this one so anybody please help?!?!?!?!


A 10kg crate is pulled up a rough 20 degree incline by a 100N force parallel to the incline. The initial speed of the crate is 1.5m/s, the coefficient of kinetic friction is .4, and the crate is pulled a distance of 5m. Determine how much work is done by
(A)the gravitational force,
(B)the100N force?
(C)What is the change in kinetic energy of the crate?
(D)What isthe speed of the crate after it is pulled 5m?
(E)How much mechanical energy is lost?

Answer 1

A) Gravity will do work of
m*g*h
m=10
g=9.8
h=sin(20)*5

B) The 100 N force works over the 5 m,
so work=F*d=100*5

C) The change in kinetic energy is the work done by the 100 N force minus the work done by gravity minus the work done by friction
=500-98*sin(20)*5-98*cos(20)*0.4*5

D) the speed of the crate is relate to the KE as .5*m*v^2
you have the starting KE and the change in KE

E) The mechanical energy lost is the work done by friction
98*cos(20)*0.4*5

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Answer 2

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