****Need help with Math Problem First person to answer it right get 10 points****?

Question

Alex invested $27,000 in two accounts: one that pays 2% simple interest and one that pays 3% simple interest. At the end of the year, his total return was $685. How much was invested in each account? Please explain your answer.

Answer 1

x + y = $27,000
&
3% of x + 2% of y = $685



=> x + y = $27,000
=> 0.03x + 0.02 y = $685

=> 1.5x + y = 34250....X by 50
=> x + y = 27,000....subtract
=> 0.5x = 7250
=> x = 14 500
&
=> y = 12 500

Answer 2

Call x the am't invested @ 2%. Then 27000 - x is invested @3%. Then 685 = .02x + .03(27000 -x), or -.01x + 810 = 685, and so .01x = 125. So x = $12,500 (@2%), and there is $14,500 @3%.

Answer 3

x(.02) + y(.03) = 685 and x + y = 27,000
from the second equation y = 27,000 - x. Substitute this into the first equation.
.02x + (27000 - x)(.03) = 685 and solve for x.
x = 12,500 plug this value into the first equation and y = 14500.

Answer 4

El planteamiento es como sigue:

Interes ganado al 2% + el interes ganado al 3 % = $ 685
monto invertido al 2% -x
monto invertido al 3% = $27,000-x
interes ganado al 2% =(x)(0.02)(1)
interes ganado al 3% = (27,000-x)(0.03)(1)
total interes ganado = 685
Ecuacion: 0.02x+0.03(27,000-x) = 685
0.02x+810-0.03x = 685
810-0.01x = 685
-0.01x = -125
125 = 0.01x
Entonces; 125/0.01= $ 12,500 y ($ 12,500*0.02 = $250)
($ 14,500*0.03= $ 435)

$ 12,500 + $ 14,500 = $ 27,000
$ 250 + $ 435 = 685.

Espero te satisfaga el proceso.

Atte.

Eduardo (Lalo) Leal

Answer 5

let $x be invested at 3% so $(27000-x) must be invested at 2%

Thus 3x/100 + 2(27000-x)/100 = 685
ie 3x +2(27000-x) = 68500
or 3x +54000 -2x = 68500
so x=14500
Therefore $14500 is invested at 3% and $12500 at 2%.

Answer 6

x*.02 + (27000 - x)*.03 = 685

Answer 7

0.02x+0.03y=685
x+y=27,000
y=27,000-x
0.02x +810 -0.03x=685
x= 12,500 and y= 14,500