A car starts from rest and accelerates at 6.00m/s^2. How far does it travel in 3.0seconds??
Thanks sooo much for the help. It is appreciated! :)
2007-10-05 06:39:10 · 4 answers · asked by PaNaSoNiCeDgE 1 in Science & Mathematics ➔ Mathematics
use this formula:
Xf = .5at^2 + Vt + Xi
the car starts from rest, its initial velocity is 0m/s
Xf = .5(6)(3)^2 + 0(3) + 0
Xf = 27m
2007-10-05 06:44:22 · answer #1 · answered by 7 · 1⤊ 0⤋
S = ut + (1/2) at^2 where S is distance travelled in time t = 3 sec. u = initial velocity = 0 as car is starting from rest.
and a = acceleration. = 6 m/s^2
S = 6 Ã 3^3 Ã 1/2
= 27 m
2007-10-05 14:04:00 · answer #2 · answered by Pranil 7 · 0⤊ 0⤋
a = 6m/s/s
t=3s
u=0m/s
s=ut+a(t*t)/2 (s is distance)
Now put the value of a,u and t.
Now, s=0+6*3*3/2
s=6*3*3/2
=27m
so distance travelled = 27 meters
2007-10-05 14:00:04 · answer #3 · answered by Anonymous · 0⤊ 0⤋
s = ut + (1/2)(a)(t²)
u = initial speed = 0
t = time in seconds
a = accn. in m/s²
s = (1/2)(6)(3²) m
s = 27 m
2007-10-05 17:31:49 · answer #4 · answered by Como 7 · 3⤊ 0⤋