bucket of water?

Question

A bucket of water with mass 6.00kg is accelerated upward by a cord of negligible mass whose breaking strength is 78.0N .

Apply Newton's second law to the bucket and find the maximum upward acceleration that can be given to the bucket without breaking the cord.

Answer 1

Newton's second law pretty much states Fnet = ma

If you draw a free-body diagram you would have Tension going up, and gravity going down.

T - mg = ma
(T-mg)/m = a
(78.0N - 9.81m/s² * 6.00kg)/(6.00kg) = a
a = 3.19 m/s² @ upward.

Answer 2

It relies upon on some components: no remember if the buckets are coated with a lid, how chilly the chilly water is, and how warm the nice and comfortable water is, and whilst they are weighed. in the event that they are weighed right now, they could desire to weight relating to the comparable. For the sake of argument, enable's say that the water are the two VERY intense (very chilly, extremely heat), and which you would be weighing them 24 hours later. With lid on: chilly water expands, so whilst it warms up, the water will flow down somewhat, so the nice and comfortable water will weigh somewhat extra. without a conceal, the chilly could desire to win, because of the fact the extremely warm water would be throwing off steam, evaporating lots quicker than the chilly one. wish this helps! (probable extra advantageous than you wanted to comprehend, huh? LOL)

Answer 3

Force = Mass x Acceleration

so...

Acceleration = Force / Mass

Acceleration = 78.0 N / 6.00 kg

1 N (Newton) = 1 kg*m / s2 (seconds squared)

so...

Acceleration = 78.0 kg*m/s2 divided by 6.00 kg leaving

Acceleration = 78/6 m/s2 = 13 m/s2 (meters per second per second)

Answer 4

Gee..

Is it F=ma?

so

a = F/m= 78/6.00=13.0m/s^2

Answer 5

Aw... it looks like someone is trying to get their homework done for them, isn't that so cute.

What ever happened to actually doing your own work?