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How many mL of 1M CuSO4 is needed for 1g Zn to completely react based on the equation : Zn(s) + CuSO4(aq) --> Cu(s) + ZnSO4(aq)
Answer: 15.3mL

2007-10-05 05:24:27 · 1 answers · asked by g2hn 3 in Science & Mathematics Chemistry

1 answers

Atomic weight: Zn=65

1gZn x 1molZn/65gZn x 1molCuSO4/1molZn x 1LCuSO4/1molCuSO4 = 0.0154L CuSO4 solution = 15.4mL CuSO4 solution

2007-10-05 06:22:18 · answer #1 · answered by steve_geo1 7 · 0 0

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