2007-10-05 04:38:00 · 4 answers · asked by ET 1 in Science & Mathematics ➔ Mathematics
x+(x+1)+[(x+1)+2]=12
3x+4=12
x=(12-4)/3
x=8/3
2007-10-05 04:42:25 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Ok - order of operations. Let's see
x+(x+1)+[(x+1)+2]=12 ; do the inner most () first
x+(x+1)+[x+3]=12 ; now we can start to combine
3x + 4 =12 ; good - let's subtract 4
3x = 8 ; almost there, divide by 3
x = 8/3 or 2 2/3 ; YES!
Always check:
8/3 + (8/3+1)+[(8/3+1) +2] =12 ??
8/3 + 3 2/3 + 5 2/3 = 12??
2 2/3 + 9 1/3 = 12??
12=12 YES!!
Hope this helps.
2007-10-05 04:52:10 · answer #2 · answered by pyz01 7 · 0⤊ 0⤋
x+(x+1)+(2x+2)=12
x+x+1+2x+2=12
3x+3=12
3x=9
x=3
2007-10-05 05:32:06 · answer #3 · answered by remo 1 · 0⤊ 0⤋
OK.... x = 8/3 What do you need from there?
Doug
2007-10-05 04:47:47 · answer #4 · answered by doug_donaghue 7 · 0⤊ 0⤋