The horizontal and verical components of the intial velocity of a projectile are 24m/s and 7m/s, respectively. Find the initial velocity of the projectile.
Thanks sooo much for the help. It is appreciated! :)
2007-10-05 03:25:16 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
it will be the square root of (sum of square of eaach velocity)
Vi = sqrt(24^2 + 7^2)
= sqrt(576 + 49)
= sqrt(625)
= 25 m/s
2007-10-05 03:30:49 · answer #1 · answered by blind_chameleon 5 · 1⤊ 0⤋
V^2 = Vh^@ + Vv^2 where V is the velocity, Vh is the horizontal component and Vv the vertical component.
V^2 = 24^2 + 7^2 = 576 + 49 = 625
V = 25 m/s
Angle of the velocity is given by
7/24 = tan theta where theta is the angle to the horizontal.
theta = tan^-1 (7/24)
= tan ^-1 (0.29)
= 16.17 degrees
2007-10-05 10:56:31 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
Draw a diagram. Draw the horizontal velocity as a (horizontal) arrow of length 24. From the tip of that arrow, draw the vertical velocity as a (vertical) arrow of length 7.
Those are the two components; you need to find their vector sum. To do that, draw a third arrow, from the tail of the horizontal component to the tip of the vertical component.
Now you have a triangle. Even better, it's a right triangle. You need to find the length of the hypotenuse, which is the diagonal arrow. Use the Pythagorean theorem to do that.
2007-10-05 10:36:39 · answer #3 · answered by RickB 7 · 1⤊ 0⤋
25 m/s
2007-10-05 10:34:08 · answer #4 · answered by Apparao V 4 · 0⤊ 0⤋