Accleration HELP NEEDED?

Question

A car starts from rest and accelerates at 6.00m/s^2. How far does it travel in 3.0seconds??


Thanks sooo much for the help. It is appreciated! :)

Answer 1

∫ 6.00 dt = 6t + C

v = 6t + C

∫ 6t dt = [6t^2]/2 = 3t^2 + C

Thus, d=3t^2 {C=0}

d=3(3)^3 = 27 m

The car will travel 27m in 3.0 seconds.

Answer 2

s = ut + 1/2 at^2

= 0 + 1/2 6 3^2

= 27 m

Answer 3

initial velocity = 0 m/s
final velocity = 6 m/s
time = 3 sec

acceleration = (Vf - Vi) / t
acceleration = (6 - 0) / 3
acceleration = 6 / 3
acceleration = 2 m/s/s

speed = 6m/s
speed x 3 sec = 6 x 3
speed x 3 sec = 18m in 3 seconds