(4z + 7)^2. Find the product?

4 ⤊

2007-10-05 00:55:13 · 4 answers · asked by . 1 in Science & Mathematics ➔ Mathematics

(4z+7)^2
=(4z)^2+2*4z*7+(7)^2
=16z^2+56z+49

2007-10-05 01:00:21 · answer #1 · answered by alpha 7 · 2⤊ 0⤋

(4z+7)(4z+7)
16z^2 + 28z + 28z + 49
16z^2 + 56z + 49

2007-10-05 08:07:11 · answer #2 · answered by devilishlyangelic91 2 · 0⤊ 0⤋

(4z + 7) (4z + 7) = 16 z Â² + 56 z + 49

2007-10-05 10:32:04 · answer #3 · answered by Como 7 · 2⤊ 1⤋

Hai " ",

(4z + 7)^2 = 16z^2 + 56z + 49 .......using (a + b)^2 = a^2 + 2ab + b^2

Is it O. K. ?!!!!!!!!...... :-)

2007-10-05 08:00:29 · answer #4 · answered by WishInvestor 3 · 0⤊ 0⤋