this is the 3rd time im asking T_T , i dont think i made the last one clear enough. so there's 2 circuits, parallel and series each with 4 bulbs (the 2 batteries are not in parallel in the parallel circuit, in both circuits the batteries are side-by-side). in the series circuit, the bulbs are lines up. in the parallel, the bulbs are in parallel, each with their own path. if it is series, is it because when energy goes through the filament (the resistor in this case) it's converted into light and heat, but when it goes past the resistor, the energy is transferred back into it's original power? what if it doesnt? does the first bulb closest to the positive ( i think energy goes positive to negative terminal) terminal appear brighter than the rest? and the fourth bulb the dimmest? what about parallel. lets say the total voltage is 12V. does each bubl get 3V ea then? please explain.
2007-10-04 12:29:18 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
Assuming they are identical bulbs:
In the series circuit all the bulbs will be the same brightness
In the parallel circuit all the bulbs will be the same brightness, but brighter than the 4 bulbs in the series circuit.
in the parallel circuit they all have the same voltage, so the current draw from the batteries will be 4x as great.
In the series circuit, the current through each bulb is the same, but the voltage is divided by 4, so each bulb is dimmer than the bulbs in the parallel circuit.
.
2007-10-04 12:38:51 · answer #1 · answered by tlbs101 7 · 3⤊ 0⤋
Light Bulbs In Series
2016-11-07 00:19:15 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Assuming that the batteries are big enough to be modeled as constant voltages, the bulbs in the parallel circuit will burn quite a bit brighter than those in the series circuit. In the parallel circuit, each bulb will receive the full sum of the voltages across both batteries (and a corresponding about of current). In the series circuit, if the bulbs are identical, each bulb will receive one quarter the sum of the voltages of the batteries and all four bulbs will receive the same current.
If these bulbs are ohmic resistors, each one will also receive about one quarter of the current in the series circuit and dissipate only one sixteenth the power as it would in the parallel circuit. However, incandescent bulbs must heat up greatly to glow and produce light. The heating increases the electrical resistance of the filaments greatly over what the resistance would be at room temperature. In practice, the current through the bulbs in series would be one half or more of the current flowing through the bulb in parallel and, if the bulb is operating at its rated voltage in the parallel circuit, the glow in the series circuit would hardly be visible.
2007-10-04 12:54:15 · answer #3 · answered by devilsadvocate1728 6 · 3⤊ 0⤋
I didn't understand most of the question, but it doesn't matter.
Right at the end you came to the nub of the problem; if the total voltage is 12 V, then in the case of a parallel circuit 12 V will flow through each bulb. In the case of a series circuit 3 V will flow throug each. Therefore the bulbs will be brighter in the parallel circuit.
2007-10-04 12:35:45 · answer #4 · answered by Robert K 5 · 3⤊ 0⤋
Assuming all bulbs have the same wattage.You failed to give us that information Kirchhoff's Law states for a parallel circuit, the the sum of the currents of each branch each branch circuit equals the total current and the voltage across each bulb is the same.The resistance of four bulbs is now one fourth the resistance of one bulb.That is if they are all equal wattage to start with. Kirchhoff's Law states for a series circuit the sum of voltage drops across each bulb equals the total voltage.The current will stay the same throughout the whole series circuit.The resistance will four times the resistance of one bulb. With that said the light bulbs of a parallel would be equal brightness and the brightness because more current flows them thus more power consumed With series circuit each bulbs drops the voltage by one fourth reducing the current flow with each bulb.Less voltage,less current.less power.Bulbs would be equal brightness but less bright. I hope this helps you see just how happens.You need to understand Ohm's Laws here too.
2016-03-13 07:03:39 · answer #5 · answered by Anonymous · 0⤊ 0⤋
In the series circuit each of the 4 bulbs gets a quarter of the 12 volts. Each sees 3 volts and lights up the exact same amount.
In the parallel circuit each of the bulbs sees the same 12 volts. That makes each light up the same amount and that amount is brighter.
Bulb position in its group makes no difference. Look at the low beam headlights on a car. They are in parallel across 12 volts and they light up to the same brightness.
2007-10-04 14:51:39 · answer #6 · answered by Rich Z 7 · 1⤊ 0⤋
the answer is that the parralel would be brighter. the reason why is that the parralel uses the same source of enegry. unlike series where you have to share the load.for example the lights in your house are in parralel. ligghts on a christmas tree are in series
2007-10-04 15:58:03 · answer #7 · answered by mel7996 3 · 0⤊ 0⤋
in series all bulbs get the same amount of current, each bulb drops 3 volts. V total = Itotal X Rtotal
all bubs have the same brightness, all have the same current,
all have the same voltage across them , all have them same wattage
watts = V X I (amps)
the R total limits the current in the loop.
in para each bulb has 12 volts across it , and RX1 resisteance
more voltage, more current, more watts
2007-10-04 12:41:17 · answer #8 · answered by mike 5 · 1⤊ 0⤋
extremely tough aspect. search onto google and yahoo. that will could actually help!
2014-12-06 16:30:34 · answer #9 · answered by Anonymous · 0⤊ 0⤋