Ontario Lotto 6/49. Just trying to aid my curiosity.
2007-10-02 16:11:24 · 6 answers · asked by Anonymous in Games & Recreation ➔ Gambling
When picking n items from m items, the formula is
mCn = m!/(n! * (m -n)!), so
49C6 = 49!/(6!*43!)
= 13,983,816
2007-10-02 17:13:00 · answer #1 · answered by John F 6 · 1⤊ 0⤋
The answer to this depends on whether you can repeat numbers.
If you can, it's 49*49*49*49*49*49 = 13,841,287,201.
If you can't, it's 49*48*47*46*45*44 = 10,068,347,520.
This is assuming that the order in which you pick them matters.
If order doesn't matter, then the formulas provided by the people above are right :).
2007-10-03 01:51:31 · answer #2 · answered by gondtb 1 · 0⤊ 0⤋
For 6/49 game there are 13,983,816 possible combinations.
If you want lottery number combinations for any other lottery games, betstarter.com has a simple odds (combinations) calculator at the following link:
http://www.betstarter.com/lottery/LottoOdds.asp
2007-10-03 01:21:58 · answer #3 · answered by Melkam Dirset 4 · 0⤊ 0⤋
I'm pretty sure the answer is 10,068,347,520 combinations. The odds of winning have to be astronomical otherwise it wouldn't make any money.
2007-10-02 23:24:08 · answer #4 · answered by c_valnes 1 · 0⤊ 0⤋
6x49=288 i think so 288 combinations
2007-10-02 23:19:50 · answer #5 · answered by Anonymous · 0⤊ 0⤋
6times49
high number, little brain.... nah, i'm just lazy. ^_^ but that's how you get it.
2007-10-02 23:20:04 · answer #6 · answered by Anonymous · 0⤊ 0⤋