i need help with this physics problem. i hav no idea how to solve it. please help me. thank you in advance.
A can of paint (volume = 3.78 10-3 m3) covers an area of 25.0 m2. What is the thickness of the paint on the wall?
2007-10-01 09:40:59 · 4 answers · asked by Quang P 2 in Science & Mathematics ➔ Engineering
Volume of a cube is L x W x H. V = LWH
Area of a square is L x W. A = LW
Substituting A for LW we have
V = AH
Transposing to get H
H = V/A
You do the math
2007-10-01 09:49:29 · answer #1 · answered by wry humor 5 · 1⤊ 1⤋
The area times the thickness of the paint must be equal to the volume of the paint so
25t=3.78x10^3 and
t = .00378/25 = .000152 meters or about .152 mm
Doug
2007-10-01 09:57:19 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
Not quite thick enough to cover the last paint on the wall.
2007-10-01 10:07:24 · answer #3 · answered by Warren W- a Mormon engineer 6 · 0⤊ 0⤋
0.00378m³ = 25m² x t (thickness).
t = 0.00378/25 = 0.0001512m
t = 0.0001512m x 1,000mm/m = 0.15mm thick.
2007-10-01 10:53:55 · answer #4 · answered by Norrie 7 · 0⤊ 0⤋