i connected a ZTX 300 transistor withe a 10k variable resistor the supply voltage was 6v , i've taken the results for every rime i increase the variable resistor size . i get these results :
Ib : 0 , 23.7 , 52.7 , 56.8 , 57.6 , 57.7 , 57.9 , 57.9
Ic : 0 , 0.12 , 0.42 , 0.68 , 1.24 , 2.89 , 5.61 , 5.62
these results in mA ...
- Does the results look correct and how do i know that ??
2007-09-29 07:38:16 · 3 answers · asked by Ahmad M. Alawi 3 in Science & Mathematics ➔ Engineering
compar your results with these http://www.zetex.com/3.0/pdf/ztx656.pdf
2007-09-29 08:13:25 · answer #1 · answered by mavis b 4 · 0⤊ 0⤋
Ic = Ib * hFE interior the lively variety. are the two base and collector currents in mA or micro and milli amps? is this for a complication-loose emitter configuation and did youpersistent it into saturation? Cant rather relate your figures to a common configuration i might take notice of.
2016-12-28 07:13:11 · answer #2 · answered by Anonymous · 0⤊ 0⤋
It looks as if you have Ib and Ic written down backwards.
Ic = Hfe*Ib up to saturation.
Doug
2007-09-29 09:18:21 · answer #3 · answered by doug_donaghue 7 · 0⤊ 0⤋