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for example initial z=6 e=6 n=8 after alpha z=4 e= 6 n=6, so there would be a -2 charge assuming C-14 has alpha reaction

2007-09-28 21:20:27 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

Technically speaking, when a nucleus releases an alpha particle, some electrons are bound to go along for the ride.
Even if they don't (given that nuclear decay is order of magnitude more energetic than ionization), sooner or later, the charge has to re-balance.

(And by the way--you probably know that already, but Yahoo onlookers may not--carbon 14 decays through beta radiation, that is a neutron turns into a proton and release an electron--this electron has enough energy to be free from the atom, or else we would not detect it)

2007-09-28 21:29:10 · answer #1 · answered by Vincent G 7 · 0 0

The electrons are swiftly recoverd since tere is a lot of energy released with many free electrons which are regained by thye atoms

2007-09-29 04:29:37 · answer #2 · answered by maussy 7 · 0 0

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