A constant force of 3.1 N to the right acts on a 17.6 kg mass for 0.43 s. what is the final velocity? Find the final velocity of the mass if it is initially moving along the x-axis with a velocity of 2.02 m/s to the left.
2007-09-28 18:01:24 · 3 answers · asked by Roxana R 1 in Science & Mathematics ➔ Physics
F-ma so
a = F/m = 3.1/17.6 = .176 m/s² to the right. Velocity is
v=at so
v = .176*.43 = .0757 m/s to the right. If it was initially moving with velocity v0, then that equation becomes
v = v0 + at and since the initial motion was to the left, (call in 'negative') the box has a finsl velocity of
-2.02 + .0757 = -1.944 m/s and the minus sign indicates it's still moving to the left.
Doug
2007-09-28 18:22:21 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋
Acceleration = force / mass = 3.1 / 17.6 = 0.1761m/s^2
Vf=Vo+at = 2.02 + ( 0.1761 x .43) = 2.0957m/s
2007-09-28 18:21:31 · answer #2 · answered by ? 3 · 0⤊ 0⤋
I'm just a fourth year high school student or Grade 10....I am still in free fall lesson...
2007-09-28 20:44:37 · answer #3 · answered by Anonymous · 0⤊ 0⤋