What is the acceleration experienced by the tip of the 1.5 cm long sweep second hand on your wrist watch?

Question

please help me to do this question ;) thanks

Answer 1

For circular motion:
acceleration = ω²r
where ω is the angular velocity in radians per second; and r is the radius

For your problem:
r = 1.5 cm
ω = (1 rev) / (60 sec) = (2π radians) / (60 sec)

You now have all the numbers you need.

Answer 2

For a body moving in a circular path will have an acceleration v² / r , where v is the linear velocity and r the radius of the circle.
Linear velocity = circumference / time
v = (2 x 22 x 1.5) / (7 x 60) = 0.157 m/s
Acceleration = v² / r = (0.157)² / 1.5 cm = 0.0164 cm/s²
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