hw. help again please just help :)?

Question

this is the question : write an equation of the line having the following properties.


HAS E Y-INTERCEPT OF -6 NAD IS PARALLEL TO THE GRAPGH OF X-3Y=8


SHOW HOW U DID IT PLEASE LIKE THE WORK CUZ ME NO GET IT .. :)

Answer 1

The first thing is to write the second line's equation in terms of Y (so it is in y=mx+b form, called slope-intercept form).

x - 3y = 8

Subtract x from both sides:
-3y = 8 - x

Divide both sides by -3
y = -8/3 + x/3

Rewrite in y=mx+b form:
y = (1/3)x + (-8/3)

This line has a slope of 1/3 and a y-intercept of -8/3.

Now you want a line that has the same slope (parallel) but a y-intercept of -6, so just replace the last part.

y = (1/3)x - 6

There's your answer.

Answer 2

The line is y=1/3x-6

The equation of a line (in slope-intercept form) is y=mx+b, where m is the slope and b is the y-intercept. The y-intercept is given as -6, so b=-6.

The slope isn't directly given, but it is given that the line whose graph we're writing is parallel to x-3y=8. Parallel lines have equal slopes, so if we can find the slope of x-3y=8, we have our slope for the new line. In order to find the slope, just put x-3y=8 into y=mx+b form and use the coefficient of x.

Start by subtracting x from both sides, which gives -3y=-x+8

Then divide by -3, which gives you y=1/3x-8/3 (note: the coefficient of x is positive because the negatives cancel out.)

The slope of the given line is therefore 1/3 and since the line you're looking for has the same slope, the equation is y=1/3x-6.

Answer 3

x-3y =8
3y=x-8
y=(1/3)x - (8/3)
you want a line parallel to that.therefore has the same slope but different y-intercept.
y = (1/3)x - 6

Answer 4

X-3Y=8 CHANGE TO Y=MX+B FORM
-X ON BOTH SIDES WHICH GIVES YOU:
-3Y=-X+8 DIVIDE BOTH SIDES BY -3
Y=1/3X+-8/3 IF IT IS PARALLEL IT HAS THE SAME SLOPE(M) JUST CHANGE THE Y INTERCEP(B) WHICH GIVES YOU: Y=1/3X-6