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If one of the charges is halved in size, then the magnitude of the force halves.
If both of the charges are doubled in size, then the magnitude of the force remains the same.
If the distance between the charges is halved, then the magnitude of the force increases by a factor of four.

2007-09-28 09:18:59 · 3 answers · asked by Anonymous in Science & Mathematics Physics

3 answers

Can you describe the setup? Taking a wild guess at what it looks like: t, f, t

2007-09-28 10:15:36 · answer #1 · answered by sojsail 7 · 0 0

If 2 capacitors are the comparable cost, then in sequence the equivalent capacitance is one million/2 the guy cost. So capacitance of each and each capacitor would be 2Cs (to a minimum of one million/Cs = one million/C1 + one million/C2). If 2 capacitors are the comparable cost, then in parallel the equivalent capacitance is the sum of the guy capacitance values. So capacitance of each and each capacitor would be 0.5Cp (with the help of way of Cp=C1+C2). so if those hybrid circuits produce an equivlent capacitance, then 2Cs = 0.5Cp or Cp=4Cs So in spite of the actuality that cost you flow alongside with your parallel capacitors to be, flow alongside with your sequence capacitors to be 4 circumstances that cost. e.g. If the guy Cp capacitors have a capacitance of two Farads, then Cs capacitors could desire to have a capacitance of 8 Farads.

2017-01-02 19:15:02 · answer #2 · answered by Anonymous · 0 0

f
f
t

2007-09-28 09:25:29 · answer #3 · answered by SteveA8 6 · 0 0

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