A) (2x + 4)
B) (2x + 1)
C) (2x - 1)
D) (x + 4)
E) (x - 4)
2007-09-28 09:14:09 · 10 answers · asked by caly c 1 in Science & Mathematics ➔ Mathematics
2x² + 7x - 4 = (2x - 1 )(x + 4 )
so C and E
2007-09-28 09:16:53 · answer #1 · answered by PeterT 5 · 0⤊ 1⤋
2x^2 + 7x - 4 = 2x - 1 and x + 4 so c and d are the answers
2007-09-28 09:18:36 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
2x^2+7x-4
(2x-1)(x+4)
Answer: C and D
2007-09-28 09:18:34 · answer #3 · answered by Grampedo 7 · 0⤊ 0⤋
2x^2+7x-4
=2x^2+8x-x-4
=2x(x+4)-1(x+4).
=(x+4)(2x-1).
so C &D are factors of2x^2+7x-4. ANS.
2007-09-28 09:27:21 · answer #4 · answered by Anonymous · 0⤊ 0⤋
2x² + 7x - 4
(2x -1)(x + 4)
So the answers are: c) and d)
2007-09-28 09:16:26 · answer #5 · answered by ignoramus 7 · 0⤊ 1⤋
2x^2+7x-4
=2x^2+8x-x-4
=2x(x+4)-1(x+4)
=(x+4)(2x-1), so the ans is c &d
2007-09-28 10:04:03 · answer #6 · answered by MAHAANIM07 4 · 0⤊ 0⤋
(2x-1)(x+4) c and d
2007-09-28 09:49:07 · answer #7 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
2x² + 7x - 4
x = [-7 +/- sqrt.(49-4(-8)]/4
x = [-7 +/- sqrt.(81)]/4
x' = (-7+9)/4 = 2/4 = 1/2
x" = (-7-9)/4 = -16/4 = -4
2x² + 7x - 4 <==> (x - 1/2)(x + 4) or (2x - 1)(x + 4)
2007-09-28 09:21:53 · answer #8 · answered by Christine P 5 · 0⤊ 0⤋
both C and D
2007-09-28 09:19:08 · answer #9 · answered by mohanrao d 7 · 0⤊ 0⤋
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2007-09-28 09:18:41 · answer #10 · answered by Tpunk 2 · 0⤊ 0⤋