B varies inversely with y2; B= 6 when y= 4?

Question

help, need a general formula

B varies inversely with y; B= 6 when y= 4? is what i meant

B varies inversely with y^2; B= 6 when y= 4? IS WHAT I MEANT... sorry

Answer 1

B = k/y

wher k is a constant

now
6 = k / 4
=> k = 6*4 = 24

therefore the formula is
B = 24 / y

Answer 2

EDIT: OK, I caught the change you maded and edited my answer.

When two variables "vary inversely" or are "inversely proportional", that means their product is a constant.

So since B varies inversely with y^2, that means B*y^2 = k for some constant k. Since B=6 when y=4, that means k is 6*(4^2) = 96. So the equation that describes the relationship is "B y^2 = 96".

SImilarly, if a variable is "directly proportional" to another, that means it's the second variable times a constant. So if we were told "B is directly proportional to y^2", then B = k * y^2. Just thought I'd mention this, since these two types of problems tend to show up together.

Answer 3

In general, to translate "a varies inversely with b", write:
a = k / b, where k represents the constant of variation.
Similarly, if the statement is "a varies proportionately with b", write:
a = kb.

Given, B = 6, when y = 4, determine the value of k:
B = k / y²
k = By² = (6)(16) = 96.

Answer 4

B is proportional to the reciprocal of y2,
therefore,
B equals k*(1/y2) where k is a constant,
so when y= 4, y2= 16,
so B = k*(1/16),
so 6 = k*(1/16),
so k = 16*6 = 96
Now that you know the proportionality constant you can plug it in & find B if you know y;
& vice - versa.

Answer 5

Hello

If b is inversely proportional to y^2, the equation is of the form b = k/y^2 (where k is a constant).

So we have

6 = (k/(6^2))

216 = k

B = 216/y^2

Hope this helps

Answer 6

B is proportionate to a constant (k) divided by y^2
Here it goes
B = k * 1/y^2
B * y^2 = k
6 * 4^2 = k
6 * 16 = k
96 = k

Thus B = 96/y^2
or y = sqrt (96/B)

Answer 7

what is the 2 next to the y?