math h.w please dont get it!!!!! help?

Question

passes through (-5,3) and is perpendicualer to the x-axis



thats the question im suppose to write and equation of the line having the following properties.




help

Answer 1

Perpendicular to the x-axis... the x-axis goes horizontal, correct? So a line perpendicular to the x-axis would go straight up and down (just like the y axis).

In other words, the x value would be constant and the y value would be any value. The equation of the line would be:

x = -5

See y can be anything, and x is constant. Graph this line and you'll see it is a vertical line going through (-5, 3)

Answer 2

first of all, to make a line perpendicular to the x-axis, u take the x-axis, which goes horizontally, and make a line virtically passing through it. Because u need it to pass through -5, 3, the three really doesn't matter because waht you're doing is making a vertical line.

so go to -5 on the x-axis and draw a vertical line going through it. Okay, so some random points from the line would be...

(-5, 50)
(-5, -19)
(-5. 0)
(-5, 1)
(-5, 1000000000)
(-5, 10)

basically, it doesn't matter what the "y" is, so long as the "x" value stays at -5, because ur making a vertical line

Answer 3

If it's perpendicular to the x-axis, then that means it has to be a vertical line.

The veritcal line that passes through (-5, 3) is just "x= -5".