The bowstring exerts an average force of 80 N on the arrow over a distance of 0.75 m. With what speed does the arrow leave the bow?
2007-09-28 06:09:48 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
You have force on the arrow and you have the mass of the arrow using these two knowns you can solve for acceleration
a = F/m
Then to find the speed that the arrow leaves the bow you would use
V^2 = Vo^2 + 2*a*deltaX
Vo is equal to 0 because it starts from rest. you just solved for a and delta X is given in the problem.... plug it all in.....
2007-09-28 06:46:39 · answer #1 · answered by Matt C 3 · 1⤊ 0⤋
I'm not sure if you have the right information to calculate that. Force = Mass x Acceleration. You have force and mass, so you're calculating acceleration, but acceleration is meters per second, per second. So I think you need some time factor to figure out end velocity.
But it's been a long time for me, so I could be wrong.
2007-09-28 06:19:43 · answer #2 · answered by rohak1212 7 · 0⤊ 0⤋