2007-09-28 02:06:30 · 6 answers · asked by . 1 in Science & Mathematics ➔ Mathematics
[208]
156/12=(13)
(13)16= [208]
maybe...
2007-09-28 02:13:29 · answer #1 · answered by Jc Da Man 2 · 0⤊ 0⤋
y varies directly as x
y = kx, k is a constant
when y=156, x=12,
156 = k(12)
k = 156/12
k = 13
when x = 16, k = 13
y = 13(16)
y= 208
208 is the answer..
i think
2007-09-28 02:18:29 · answer #2 · answered by beckyyyyyyyyyyyyyyyyyyyyyyy 1 · 0⤊ 0⤋
If Y varies directly as X , then Y is a linear multiple of X..
Y = (a) * X
Now, we have to solve for the co-efficient (a)
(a) = Y / x
(a) = 156 / 12 = 13
Therefore,
Y = 13 * X
To find y when x = 16 :
Y = 13 * (16) = 208
elementary Watson!
2007-09-28 02:23:34 · answer #3 · answered by OK Whatever 1 · 0⤊ 0⤋
y varies directly as x,
thus,x/y is a constant.
thus,
12/156=y/16
by cross multiplication, we get,
12y=156.16
y=156 . 16/12
y=13 . 12
y=208
2007-09-28 02:30:09 · answer #4 · answered by Anonymous · 0⤊ 0⤋
y = k x
156 = k (12)
k = 13
y = 13 x 16
y = 208
2007-09-28 06:28:29 · answer #5 · answered by Como 7 · 0⤊ 0⤋
y ∝x
y = k(x)
y/x= k
156/ 12= k
k=13
y= 13(16)
y= 208
2007-09-28 02:15:04 · answer #6 · answered by ? 2 · 0⤊ 0⤋