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like if your given a time and angle and have to find all other possible info.. whats difference between horizonta & vertical components??

2007-09-27 13:14:13 · 2 answers · asked by Anonymous in Science & Mathematics Physics

BOO no answers. you all suck

2007-09-28 08:43:50 · update #1

2 answers

First of all, horizontal & vertical components are perpendicular to one another. Therefore, they may be treated separately.
Given that, if there is no friction force horizontally, horizontal movement would have a constant velocity/ speed. That would greatly simplify the issue, and/ or provide useful information.
Vertically, there is always gravity. Since you may not be able to turn the gravity off, you have to consider the downward accelaration, or gravitational force.
There is not a single formula to cover all the physical mechanical problems. But all can be solved with understanding and consideration in physical principles.
Now take your example of given the in-air time, t, of a projectile, and the angle, theta, the initial velocity makes with the horizon, we can find other information in simple physics problem such as without considering the air friction.
Given the in-air time t, the projectile reaches the maximum height in t/2. Let the initial velocity to be V. The horizontal and vertical components of V must be: V*cos(theta) and V*sin(theta), respectively. Thus:
V*sin(theta) = g*(t/2)
where g is the gravitational accelaration 9.81m/s^2. From this V can be solved. Hence the maximum height is 0.5*g*(t/2)^2, and the projectile would land t*V*cos(theta) away.

2007-09-28 16:24:12 · answer #1 · answered by Hahaha 7 · 0 0

In element projection, optimum top is ideal on the start. Horizontal speed continues to be consistent. The time in element projection is largely the time for an merchandise to fall to floor (vertically) from the top it replaced into projected from. the cost interior the Y airplane starts at 0 at launch, and achieves a optimum only formerly impact with floor. the in worry-free words idea is to remember that horizontal speed continues to be consistent (ignoring friction), even as the vertical speed (also ignoring friction) adjustments in worry-free words relative to the time it takes for a element fired projectile to drop vertically to floor element, in spite of ways far it has travelled. an same applies for projectiles fired at an attitude or vertically, except the initial vertical speed falls to 0 at optimum top, then will strengthen to a optimum speed down, only formerly impact.

2016-10-20 03:43:22 · answer #2 · answered by ? 4 · 0 0

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