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2007-09-27 04:19:02 · 3 answers · asked by lacrosse13bb 3 in Science & Mathematics Engineering

There 100% is a sampling frequency because it is impossible to send the infinite information from a sensor to a computer. The data must be quantized so teh computer can read it. Sorry, but the Top Contributer is wrong.

2007-09-27 04:48:51 · update #1

3 answers

I have heard this from auto technician 'shop talk', but I don't have any reference to back it up: 1 sample per second.

That makes sense to me, average gas mixtures in the exhaust are not going to change much faster, anyway -- even at high RPMs.

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2007-09-27 05:07:27 · answer #1 · answered by tlbs101 7 · 1 1

They don't sample, they are constantly on and their resistance changes depending on whether they are exposed to O2 or CO or CO2.

They normally run at 0.45 volts but as the exhaust mixture varies and changes the voltage, the mixture is compensated to get it back to 0.45 or stasis.

*** Its two electrodes provide an output voltage corresponding to the quantity of oxygen in the exhaust relative to that in the atmosphere. An output voltage of 0.2 V (200 mV) DC represents a lean mixture. That is one where the amount of oxygen entering the cylinder is sufficient to fully oxidize the carbon monoxide (CO), produced in burning the air and fuel, into carbon dioxide (CO2). A reading of 0.8 V (800 mV) DC represents a rich mixture, one which is high in unburned fuel and low in remaining oxygen. The ideal point is 0.45 V (450 mV) DC; this is where the quantities of air and fuel are in the optimum ratio, called the stoichiometric point, and the exhaust output will mainly consist of fully oxidized CO2.

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2007-09-27 04:32:48 · answer #2 · answered by muddypuppyuk 5 · 0 1

it would have to be pretty darn fast. i would imagine at least once per cylindar fire.

2007-09-27 04:26:54 · answer #3 · answered by swatthefly 5 · 0 3

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