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2007-09-26 10:18:56 · 6 answers · asked by lsjfl;ajfoiweajfmsdfjkj =D 1 in Food & Drink Cooking & Recipes

6 answers

YEAST is a living organism and it thrives in a warm and humid environment.
Regular dry yeast needs to be activated
at 105*F to 115*F once it becomes activated and mixed with the ingredients
nessary to make bread it requires a warm and moist place to feed off the sugars and
starches to produce carbon dioxide which in turn causes the bread to rise.
Yeast likes the temperature to be 80*F to 84*F
And the humidity 84% to 87%.I hope this
helps you. injoy your bread making. jim b

2007-09-26 10:48:31 · answer #1 · answered by Anonymous · 1 0

It has to do with the activation of the yeast. Yeast is a live culture that needs heat to grow. At low temperatures (0-10 C) yeast will not grow, but not die either. At temperatures 10-37 C yeast will grow and multiply, faster at higher temperatures with an optimal growth at 30 or 37 C (that depends on the species). At higher temperature the cells become stressed, meaning that their content becomes damaged and which can be repaired to some degree. At high temperatures (>50 C) the cells die. The bacteria can
survive freezing under certain conditions.

2007-09-26 17:23:48 · answer #2 · answered by Anonymous · 1 0

If it's yeast bread, the yeast is a living thing that requires a certain narrow range of temperature to work it's magic. Too cold and it won't work; too hot and it dies. You want your bread to rise, you gotta keep it warm - but not too warm.

2007-09-26 23:34:52 · answer #3 · answered by Anonymous · 0 0

The yeast that turn sugar into carbon dioxide are more active at warmer temperatures, hence bread rises faster.

Doug

2007-09-26 17:22:22 · answer #4 · answered by doug_donaghue 7 · 0 0

The temp. has to be right for the yeast to work and make the bread rise. Temp. is very important in candy making too.

2007-09-30 15:44:15 · answer #5 · answered by curious connie 7 · 0 0

Yeast is only active between 8 and and about 30 degrees

2007-09-26 17:23:09 · answer #6 · answered by Anonymous · 0 0

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