imagine a circuit which only has a switch and wire and cell and no bulb.
2007-09-26 09:08:45 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
No, the only energy loss will be that loss which occurs in the cell itself. Although negligible, the cell will decrease slowly until dead.
as for stray capacitance, a cell is a DC source, and as such once a capactanceis charged, it will use no energy at all, trick question or not.
2007-09-26 09:14:55 · answer #1 · answered by Dondi 7 · 2⤊ 0⤋
No, there is no waste because until the bulb - or something else completes the circuit, the cell (electron pump) is effectively on standby - and not generating any power.
Mark
2007-09-26 09:13:22 · answer #2 · answered by Mark T 6 · 1⤊ 0⤋
You "consume" energy by having a circuit that allows electrons to move along a path. With no bulb, you have no path and not energy being consumed.
2007-09-26 09:16:33 · answer #3 · answered by united9198 7 · 0⤊ 0⤋
@Dondi: The vast majority of light bulbs are powered by AC. AC has continuous (120 times per second) charging/discharging of wires, causing a very tiny (but non-zero) amount of energy to be lost.
But there is no meaningful amount of energy wasted.
2007-09-26 11:14:50 · answer #4 · answered by tinfoil666 3 · 0⤊ 0⤋
No, it's not being wasted. If no current flows (because of no complete circuit) then no energy is consumed.
Doug
2007-09-26 09:28:04 · answer #5 · answered by doug_donaghue 7 · 0⤊ 0⤋
they only incorporate a small quantity of Mercury (approximately 5 g) and it is customarily absorbed with the aid of the phosphor with the aid of the time you throw them out. utilising them somewhat prevents extra Mercury from entering into the ambience when you consider which you keep capacity meaning that there will be much less burning of coal (which releases mercury). you in basic terms ought to rigidity approximately in case you're pregennt or in case you have infants around yet there is extra possibility in ingesting fish then smashing some lights furniture. in case you're taking your bulbs to the situation you obtain them from they are going to many times remove them for you.
2016-10-20 01:45:43 · answer #6 · answered by Anonymous · 0⤊ 0⤋
No loss of energy from the circuit, because it's open.
However, the battery will slowly deplete until it's dead no matter what.
2007-09-26 09:19:56 · answer #7 · answered by solo 3 · 0⤊ 0⤋
No, because it's an open-circuit.
Yes, due to stray capacitance in maintaining voltage in the hot wire.
It depends on whether or not this is a trick question.
2007-09-26 09:12:55 · answer #8 · answered by Xero Sinko 2 · 0⤊ 0⤋
No,,,because the circuit would be open and no current would flow.
2007-09-26 09:16:16 · answer #9 · answered by java 4 · 0⤊ 0⤋
no it isint because their is nothing being used until you put in a bulb
2007-09-26 09:16:30 · answer #10 · answered by Anonymous · 0⤊ 0⤋