7(3 x+ 4)= 8( 2x+5)+13?

21x + 28 = 16x + 53
5x = 25
x = 5

2007-09-25 19:27:43 · answer #1 · answered by Como 7 · 2⤊ 0⤋

Solving these type of problems you need to remember the rule MDAS, Multiply - divide - add - subtract, and the different properties.

So for 7(3 x+ 4)= 8( 2x+5)+13

you first need to use distributive property of multiplication resulting to:

21x + 28 = 16x + 40 + 13; add same terms
21x + 28 = 16 x + 53; subtract 16x and 28 0n both sides
21x - 16x = 53 - 28; perform operation
5x = 25
x = 5

Hope I was able to help. Just always remember MDAS. okay?

2007-09-26 02:52:09 · answer #2 · answered by hayaku_raven22 2 · 0⤊ 1⤋

First distribute on left and right side:
7*3x + 7*4 = 8*2x + 8*5 + 13
21x + 28 = 16x + 40 + 13
21x + 28 = 16x + 53

Now put your x's on one side and numbers on the other
21x - 16x = 53 - 28
5x = 25

Now divide the 5 on both sides
5x/5 = 25/5

Solution is therefore

x = 5

2007-09-26 02:29:35 · answer #3 · answered by Anonymous · 1⤊ 1⤋

7(3x + 4)= 8(2x + 5)+13
21x + 28 = 16x + 40 + 13
21x + 28 = 16x + 53
21x - 16x = 53 - 28
5x = 25
x = 5

2007-09-26 02:26:50 · answer #4 · answered by redy_salem 2 · 0⤊ 0⤋

7(3 x+ 4)= 8( 2x+5)+13

First you need to use the distrubution method:
21x + 28 = 16x +40 +13

Add 40 and 13
21x +28 = 16x +53

Subtract 16x on both sides
5x +28 = 53

Subtract 28 on both sides
5x = 25

Divide 5 on both sides
x = 5

Hope this helps =]

2007-09-26 02:26:12 · answer #5 · answered by marikrismas 3 · 0⤊ 0⤋

Distribute 7:
21x + 28 = 8(2x + 5) + 13

Distribute 8:
21x + 28 = (16x + 40) + 13

combine the like terms:
21x + 28 = 16x + 53

subtract 16x both sides:
21x - 16x + 28 = 16x - 16x + 53

combine them:
5x + 28 = 53

subtract both sides by 28:
5x + 28 - 28 = 53 - 28

combine:
5x = 25

divide both sides by 5:
x = 5

2007-09-26 02:25:59 · answer #6 · answered by Alex ^^ 2 · 0⤊ 0⤋

7 (3x + 4) = 8 ( 2x + 5) + 13
21x + 28 = 16x + 40 + 13
21x + 28 = 16x + 53
5x + 28 = 53
5x = 25
x = 5

2007-09-26 02:45:58 · answer #7 · answered by The Glorious S.O.B. 7 · 0⤊ 1⤋

Ans: x = 5.

Solution:
7(3 x+ 4)= 8( 2x+5)+13
or, 21x + 28 = 16x + 53
or, 5x = 25
hence, x = 5

2007-09-26 02:30:17 · answer #8 · answered by truthseeker 2 · 0⤊ 1⤋

First, use the distributive property to simplify the equation:

21x + 28 = 16x + 30 + 13

Then combine like terms:

21x + 28 = 16x + 43

Next, perform the subtraction property of equality on either the integers or variables (I chose integers):

21x = 16x + 15

Perform the subtraction property of equality again:

5x = 15

Finally, solve.

2007-09-26 02:25:37 · answer #9 · answered by Kal 4 · 0⤊ 0⤋

x =5
21x + 28 = 16x +40 +13
21x + 28 = 16x +53
21x=16x+25
5x=25
x=5

2007-09-26 02:26:36 · answer #10 · answered by JM 6 · 0⤊ 0⤋

7(3 x+ 4)= 8( 2x+5)+13?

13 answers