Physics Problem!!!? Force of static friction?

Question

A force F = 72.8 N acts at an angle = 37degrees
with respect to the horizontal on a block of
mass m = 22.3 kg, which is at rest on a
horizontal plane.
The acceleration of gravity is 9.81 m/s2 :
If the static frictional coefficient is us / 0.8,
what is the force of static friction?

Answer 1

You should specify whether this force "F = 72.8 N at an angle = 37degrees with respect to the horizontal on a block of
mass m = 22.3 kg" is upward or down ward.
Let me assume it is downward.
The block mass m = 22.3 kg, the weight of the block is mg.
The force F adds an additional downward force component onto the block:
F*sin(37degree)
Therefore the force of static friction is:
{F*sin(37degree) + mg}*(static frictional coefficient)
= {72.8*sin(37degree) + 22.3*9.81}*0.8 (N)
= 210 (N)