Need help plzzz?

0 ⤊

Assume that you start with 4 mole of magnesium metal, determine:

1. The number of grams of MgO(s) that would be produced in the following reaction (enter your answer with 4 significant figures):

Mg(s) + 1/2 O2(g) -----> MgO(s)

2007-09-25 16:00:24 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

2 answers

You created 4 moles of magnesium oxide, this is a very simple problem; here's what the weight will be:

[24.305 + 16.00] x 4 = 161.2g

(The weight of one mole MgO x 4)

2007-09-25 16:19:26 · answer #1 · answered by Flying Dragon 7 · 0⤊ 0⤋

First of 4 moles of magnesium is 4x24.405 amu = 97.62 g and 0.5 moles of oxygen is 32x 0.5= 16g so 97.62+16=113.62g of Magnesium oxied

2007-09-25 23:08:33 · answer #2 · answered by Anonymous · 0⤊ 0⤋