i need help on alg 2 question.?

Question

solve this equation 40a^2 + 4a = 0 if possible can you show the steps

Answer 1

Well, one solution is a=0. If a≠0, then dividing by a yields:

40a+4=0
40a=-4
a = -1/10

So a=0 ∨ a=-1/10

Answer 2

40a^2 + 4a = 0

4a ( 10a + 1 ) = 0

so the answers have to be a= -1/10 and a = 0

Answer 3

40a^2 + 4a = 0
<==>
4a(10a + 1) = 0
<==>
a = 0
or
10a + 1 = 0
10a = -1
a = -1/10

Answer: a = 0 or a = -1/10

Answer 4

factor out 4a 4a (10a+1)=0
set 4a equal to 0 4a=0
solve or a a=0

set (10a+1) equal to 0 10a+1=0
solve for a 10a= -1
a= -1/10

so a = 0 and a= -1/10

Answer 5

algoritham::
factorise the equation and equate all the factors to 0 and then calculate x this is the root
for your question
4a(10a+1)=0
so a=0 or 10a+1=0
so a=0 or a=-1/10

in general,,
if equation is ax^2+bx+c=0
the roots are x=[-b+sqrt(b^2-4ac)]/2a
and x=[-b-sqrt(b^2-4ac)]/2a