ok so in the older movies Joda is hiding from the empire right(true/false)?so when is the first time we see yoda in the movies and what hapens to obi-wan whe he fights darth vader he just goes poof and why is the red squadron so awesome whats their deal
2007-09-25 15:50:43 · 5 answers · asked by Human No.2543324757 2 in Entertainment & Music ➔ Movies
yup, yoda's hiding. we first see yoda in the empire strikes back (episode 5). red squadron aren't really that great at first. they all die except luke and wedge. luke later takes the remains of red squad to form rogue squadron though.
2007-09-25 15:54:25 · answer #1 · answered by zenmaster_moomoo 2 · 1⤊ 0⤋
Yoda is in hiding, i guess you could call it that. Yoda first appears in Empire Strikes back. Obi wan becomes "one with the force". pretty much all jedi dissapear, if they know how to....
Red Squadron is really actually Rogue Squadron. They are the Best of the Best. the Elite of the Elite.
2007-09-28 23:37:22 · answer #2 · answered by Garviel Loken 3 · 0⤊ 0⤋
Yoda's 1st appearance is Empire Strikes Back (part 5). Obi Wan is so controlled by the force that when he dies he becomes a part of the force. As for the red squadron they are the special forces, they are the best of the best. Kinda like out Navy Seals, Green Barets, etc.
2007-09-25 22:55:48 · answer #3 · answered by ? 5 · 0⤊ 0⤋
for one, yoda is placing himself in hermitude to hide from the empire and I guess he thinks he failed or something.... obi-wan goes and joins the force thats why he said he will be more powerful than darth will ever be..... the red squadron is like the best of the best fighter pilots and besides, they are on the writers side so they just have to kick major butt............
2007-09-25 22:54:56 · answer #4 · answered by Jay P 5 · 0⤊ 0⤋
Yoda feels betrayed that why he's hiding,Obi Won disappears because this soul leaves when he fight another Jedi!! spacial army.. i guess the are real people not clones...appointed by the chancellor Palatine.
2007-09-26 02:45:15 · answer #5 · answered by ? 7 · 0⤊ 2⤋