3Cu(s) + 8HNO3(aq) ——> 3Cu(NO3)2(aq) + 2NO(g) + 4H2O(l)
What happens in the above reaction? Why?
(a) Redox (State what is being oxidized and what is being reducted)
(b) Acid-Base
(c) Precipitattion Reaction
2007-09-25 15:42:43 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
This is an oxidation/reduction reaction.
Oxidation states on reactant side:
Cu = 0
H = +1
N = +5
O = -2
Oxidation states on product side:
Cu = +2
N = +5 and +2
O = -2
H = +1
Copper is being oxidized. Nitrogen is being reduced.
2007-09-25 15:48:07 · answer #1 · answered by lhvinny 7 · 1⤊ 0⤋
It is a Redox Reaction
A Redox Reaction is a reaction in which elements change charge. In this case it is Cu --> Cu+2 (Cu is getting oxidized) and N5+ --> N2+ + N5+ (N is getting reduced).
An Acid base is a reaction in which the reactants contain OH- and H+ ions, however in this case there are only H+ ions.
A Precipitate Reaction is a reaction in which a solid is formed from aq ions, however in this case there is no solid formed, only a gas, liquid, and an aq solution.
2007-09-25 17:50:42 · answer #2 · answered by Zorba 1 · 1⤊ 0⤋
dont know
2015-10-29 00:42:56 · answer #3 · answered by carmella 1 · 0⤊ 1⤋