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3 consecutive even integers are given by x, x+2, and x+4
Find these three numbers such that the sum of the first, two times the second, and three times the third is 124. pliss someone explain how you get to ya answer

2007-09-25 15:32:48 · 8 answers · asked by petite fille 2 in Science & Mathematics Mathematics

8 answers

solution:
x + 2 (x+2) + 3 (x+4) = 124

x + 2x + 4 + 3x + 12 = 124

6x + 16 = 124

6x = 124 - 16 = 108

x = 108/6 = 18

2007-09-25 15:38:28 · answer #1 · answered by Anonymous · 0 0

I assume you mean the sum of the first, 2 times the second, and 3 times the third = 124. Well, x + 2(x+2) + 3(x + 4) = x + 2x + 4 + 3x + 12 = 6x + 16. So if 6x + 16 = 124, 6x = 108, and x = 18. So the three integers are 18, 20, and 22. Checking: 18 + 40 + 66 = 124.

2007-09-25 22:37:23 · answer #2 · answered by Howard H 7 · 0 0

Ok, before we place limits on the answer, first lets get the equation that the question is asking for:

X + 2(X+2) + 3(X+4) = 124

Then we simplify:

X + 2X + 4 + 3X + 12 = 124
6X + 16 = 124

Solve for X:

6X + 16 - 16 = 124 -16
6X = 108
X = 108/6 = 18
X = 18

Now just plug 18 into the original integers and you get:

X = 18, X+2 = 20, X+4 = 22

Hope this helps.

2007-09-25 22:40:05 · answer #3 · answered by gradstudent309 3 · 0 0

well you just plug in the numbers into the worded sentence, its about reading math. they gave you the 3 numbers, so then the rest is just reading the sentence and figuring it out.
sum of the first (x) plus (+) two times the second (2(x+2)) plus(+) three times the third(3(x+4)) is (=) 124

x+2(x+2)+3(x+4)=124
x+2x+4+3x+12=124
6x+16=124
6x=108
x=18
so then the numbers are 18(x), 20(x+2), 22(x+4)

2007-09-25 22:42:15 · answer #4 · answered by LeonardoDaVinci 2 · 0 0

1st = x
2nd = x+ 2
3rd = x + 4

first + 2 times second + 3 times third
x + 2(x + 2) + 3(x + 4) = 124
x + 2x + 4 + 3x + 12 = 124, combine like terms
6x + 16 = 124, subtract 16
6x =108
x = 18

18, 20, 22

2007-09-25 22:39:25 · answer #5 · answered by sfroggy5 6 · 0 0

Ok if you need x+ 2*(x+2) and 3*(x+4) to equal 124

then.....

x+2(x+2)+3(x+4)=124
that equals
x+2x+4+3x+12=124
or
6x+16=124
subtract 16 from both sides and you have
6x=108
divide both sides by 6 and you have
x=18 x+2=20 and x+4=22

Hope that is easy enough to understand!

2007-09-25 22:40:09 · answer #6 · answered by wes m 2 · 0 0

first is x
two times the second is 2(x+2)
three times the third means 3(x+4)
there fore
x+2(x+2)+3(x+4) = 124
6x+16 = 124
6x= 108
x=18

2007-09-25 22:37:21 · answer #7 · answered by shuaib 2 · 0 0

18, 20, 22

x + 2(x+2) + 3(x+4) = 124

distribute and solve for X

2007-09-25 22:38:37 · answer #8 · answered by vballchic 1 · 0 0

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